(0.5x^2)-(10x)+(32)=0

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Solution for (0.5x^2)-(10x)+(32)=0 equation:


Simplifying
(0.5x2) + -1(10x) + (32) = 0

Remove parenthesis around (10x)
(0.5x2) + -1 * 10x + (32) = 0

Multiply -1 * 10
(0.5x2) + -10x + (32) = 0
(0.5x2) + -10x + 32 = 0

Reorder the terms:
32 + -10x + (0.5x2) = 0

Solving
32 + -10x + (0.5x2) = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
0.5 the coefficient of the squared term: 

Divide each side by '0.5'.
64 + -20x + x2 = 0

Move the constant term to the right:

Add '-64' to each side of the equation.
64 + -20x + -64 + x2 = 0 + -64

Reorder the terms:
64 + -64 + -20x + x2 = 0 + -64

Combine like terms: 64 + -64 = 0
0 + -20x + x2 = 0 + -64
-20x + x2 = 0 + -64

Combine like terms: 0 + -64 = -64
-20x + x2 = -64

The x term is -20x.  Take half its coefficient (-10).
Square it (100) and add it to both sides.

Add '100' to each side of the equation.
-20x + 100 + x2 = -64 + 100

Reorder the terms:
100 + -20x + x2 = -64 + 100

Combine like terms: -64 + 100 = 36
100 + -20x + x2 = 36

Factor a perfect square on the left side:
((x) + -10)((x) + -10) = 36

Calculate the square root of the right side: 6

Break this problem into two subproblems by setting 
((x) + -10) equal to 6 and -6.

Subproblem 1

(x) + -10 = 6 Simplifying (x) + -10 = 6 x + -10 = 6 Reorder the terms: -10 + x = 6 Solving -10 + x = 6 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + x = 6 + 10 Combine like terms: -10 + 10 = 0 0 + x = 6 + 10 x = 6 + 10 Combine like terms: 6 + 10 = 16 x = 16 Simplifying x = 16

Subproblem 2

(x) + -10 = -6 Simplifying (x) + -10 = -6 x + -10 = -6 Reorder the terms: -10 + x = -6 Solving -10 + x = -6 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + x = -6 + 10 Combine like terms: -10 + 10 = 0 0 + x = -6 + 10 x = -6 + 10 Combine like terms: -6 + 10 = 4 x = 4 Simplifying x = 4

Solution

The solution to the problem is based on the solutions from the subproblems. x = {16, 4}

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